x^2+17x=200

Solution for x^2+17x=200 equation:

x^2+17x=200

We move all terms to the left:

x^2+17x-(200)=0

a = 1; b = 17; c = -200;
Δ = b2-4ac
Δ = 172-4·1·(-200)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-33}{2*1}=\frac{-50}{2}
=-25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+33}{2*1}=\frac{16}{2}
=8
$